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Crypto
2019/04/05

Training: Crypto - Caesar I

提示是凯撒密码，写了个凯撒密码加解密的Python程序，代码如下：

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def encode():
    message = input("输入明文：")
    n = int(input("输入密钥数字："))
    translated = ''
    for i in message:
        if i == ' ':
            translated += ' '
        else:
            translated += chr((ord(i)-65+n)%26+65)
    print(translated)
def decode():
    message = input("输入密文：")
    for key in range(26):
        translated = ''
        for i in message:
            if i == " ":
                translated += " "
            else:
                translated += chr((ord(i)-65-key)%26+65)
        print("密钥为%s，明文为：%s" % (key,translated))
mode = input("需要加密输入1，需要解密输入2：")
if mode == "1":
    encode()
elif mode == "2":
    decode()
else:
    print("错误！")

输入CQN ZDRLT KAXFW OXG SDVYB XENA CQN UJIH MXP XO LJNBJA JWM HXDA DWRZDN BXUDCRXW RB LXMXXQRPRJUX后运行结果：
image

Training: Crypto - Transposition I

置换加密，根据前面的oWdnreuf.l推测这个单词为Wonderful.，由此推测出密钥为1032547698（解密）
写了一个简单的小程序进行解密：

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a = "oWdnreuf.lY uoc nar ae dht eemssga eaw yebttrew eh nht eelttre sra enic roertco drre . Ihtni koy uowlu dilekt  oes eoyrup sawsro don:wd rodeapmomb.l"
key = "1032547698"
b = []
for i in range(len(a)):
    b.append(int(key[i%len(key)])+len(key)*(int(i/len(key))))
c = list(map(lambda x:a[x],b))
print(''.join(c))

运行结果为：
image

Training: Crypto - Caesar II

凯撒密码，密钥数量从26扩大到128

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def decode(message):
    for key in range(128):
        isRight = True
        translated = ''
        for i in message:
            translated += chr((key+i)%128)
        print("密钥为%s，明文为：%s" % (key,repr(translated)))
message = "5A 02 02 77 20 7D 02 75 3F 20 0C 02 08 20 06 02 7F 09 78 77 20 02 01 78 20 00 02 05 78 20 76 7B 74 7F 7F 78 01 7A 78 20 7C 01 20 0C 02 08 05 20 7D 02 08 05 01 78 0C 41 20 67 7B 7C 06 20 02 01 78 20 0A 74 06 20 79 74 7C 05 7F 0C 20 78 74 06 0C 20 07 02 20 76 05 74 76 7E 41 20 6A 74 06 01 3A 07 20 7C 07 52 20 44 45 4B 20 7E 78 0C 06 20 7C 06 20 74 20 04 08 7C 07 78 20 06 00 74 7F 7F 20 7E 78 0C 06 03 74 76 78 3F 20 06 02 20 7C 07 20 06 7B 02 08 7F 77 01 3A 07 20 7B 74 09 78 20 07 74 7E 78 01 20 0C 02 08 20 07 02 02 20 7F 02 01 7A 20 07 02 20 77 78 76 05 0C 03 07 20 07 7B 7C 06 20 00 78 06 06 74 7A 78 41 20 6A 78 7F 7F 20 77 02 01 78 3F 20 0C 02 08 05 20 06 02 7F 08 07 7C 02 01 20 7C 06 20 78 7F 05 77 03 7C 7B 7B 74 01 74 7A 41"
message = message.split(" ")
a = [int(i,16) for i in message]
decode(a)

为了在结果中直接输出\r而不转义，print时用了repr( )

repr()： 产生一个解释器易读的表达形式。
image

Training: Crypto - Substitution I

用https://quipqiup.com/
image

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